x^2=435

Solution for x^2=435 equation:

x^2=435

We move all terms to the left:

x^2-(435)=0

a = 1; b = 0; c = -435;
Δ = b2-4ac
Δ = 02-4·1·(-435)
Δ = 1740
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1740}=\sqrt{4*435}=\sqrt{4}*\sqrt{435}=2\sqrt{435}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-2\sqrt{435}}{2*1}=\frac{0-2\sqrt{435}}{2}
=-\frac{2\sqrt{435}}{2}
=-\sqrt{435}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+2\sqrt{435}}{2*1}=\frac{0+2\sqrt{435}}{2}
=\frac{2\sqrt{435}}{2}
=\sqrt{435}
$